Base | Representation |
---|---|
bin | 10010010110111010010001 |
3 | 100001111102021 |
4 | 102112322101 |
5 | 2212444213 |
6 | 251051441 |
7 | 55622263 |
oct | 22267221 |
9 | 10044367 |
10 | 4812433 |
11 | 279771a |
12 | 1740b81 |
13 | cc65c2 |
14 | 8d3b33 |
15 | 650d8d |
hex | 496e91 |
4812433 has 2 divisors, whose sum is σ = 4812434. Its totient is φ = 4812432.
The previous prime is 4812427. The next prime is 4812481. The reversal of 4812433 is 3342184.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4804864 + 7569 = 2192^2 + 87^2 .
It is a cyclic number.
It is not a de Polignac number, because 4812433 - 217 = 4681361 is a prime.
It is a super-2 number, since 2×48124332 = 46319022758978, which contains 22 as substring.
It is equal to p336256 and since 4812433 and 336256 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 4812398 and 4812407.
It is not a weakly prime, because it can be changed into another prime (4812413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2406216 + 2406217.
It is an arithmetic number, because the mean of its divisors is an integer number (2406217).
Almost surely, 24812433 is an apocalyptic number.
It is an amenable number.
4812433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4812433 is an equidigital number, since it uses as much as digits as its factorization.
4812433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2304, while the sum is 25.
The square root of 4812433 is about 2193.7258260776. The cubic root of 4812433 is about 168.8320519124.
The spelling of 4812433 in words is "four million, eight hundred twelve thousand, four hundred thirty-three".
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