Base | Representation |
---|---|
bin | 100011000001101101100… |
… | …1000001100000010111001 |
3 | 122001012212201001112111022 |
4 | 1012003123020030002321 |
5 | 1112333123132301223 |
6 | 14123312254312225 |
7 | 1004542251350504 |
oct | 106033310140271 |
9 | 18035781045438 |
10 | 4814039728313 |
11 | 1596693a1a012 |
12 | 658bb01b8675 |
13 | 28bc67683c4a |
14 | 12900216013b |
15 | 85356b2bac8 |
hex | 460db20c0b9 |
4814039728313 has 2 divisors, whose sum is σ = 4814039728314. Its totient is φ = 4814039728312.
The previous prime is 4814039728297. The next prime is 4814039728349. The reversal of 4814039728313 is 3138279304184.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4711816931584 + 102222796729 = 2170672^2 + 319723^2 .
It is a cyclic number.
It is not a de Polignac number, because 4814039728313 - 24 = 4814039728297 is a prime.
It is not a weakly prime, because it can be changed into another prime (4814039724313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2407019864156 + 2407019864157.
It is an arithmetic number, because the mean of its divisors is an integer number (2407019864157).
Almost surely, 24814039728313 is an apocalyptic number.
It is an amenable number.
4814039728313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4814039728313 is an equidigital number, since it uses as much as digits as its factorization.
4814039728313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3483648, while the sum is 53.
The spelling of 4814039728313 in words is "four trillion, eight hundred fourteen billion, thirty-nine million, seven hundred twenty-eight thousand, three hundred thirteen".
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