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4814039728313 is a prime number
BaseRepresentation
bin100011000001101101100…
…1000001100000010111001
3122001012212201001112111022
41012003123020030002321
51112333123132301223
614123312254312225
71004542251350504
oct106033310140271
918035781045438
104814039728313
111596693a1a012
12658bb01b8675
1328bc67683c4a
1412900216013b
1585356b2bac8
hex460db20c0b9

4814039728313 has 2 divisors, whose sum is σ = 4814039728314. Its totient is φ = 4814039728312.

The previous prime is 4814039728297. The next prime is 4814039728349. The reversal of 4814039728313 is 3138279304184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4711816931584 + 102222796729 = 2170672^2 + 319723^2 .

It is a cyclic number.

It is not a de Polignac number, because 4814039728313 - 24 = 4814039728297 is a prime.

It is not a weakly prime, because it can be changed into another prime (4814039724313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2407019864156 + 2407019864157.

It is an arithmetic number, because the mean of its divisors is an integer number (2407019864157).

Almost surely, 24814039728313 is an apocalyptic number.

It is an amenable number.

4814039728313 is a deficient number, since it is larger than the sum of its proper divisors (1).

4814039728313 is an equidigital number, since it uses as much as digits as its factorization.

4814039728313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3483648, while the sum is 53.

The spelling of 4814039728313 in words is "four trillion, eight hundred fourteen billion, thirty-nine million, seven hundred twenty-eight thousand, three hundred thirteen".