Base | Representation |
---|---|
bin | 110110101111110001000010… |
… | …0110111010101000000100111 |
3 | 2100011001002221121101100211012 |
4 | 1231133202010313111000213 |
5 | 1001104240003323332012 |
6 | 4424102500345132435 |
7 | 203301061046632226 |
oct | 15537420467250047 |
9 | 2304032847340735 |
10 | 481553962324007 |
11 | 12a48a985711911 |
12 | 4601447378a11b |
13 | 17891461425bb1 |
14 | 86cb49c502cbd |
15 | 3aa14cc588622 |
hex | 1b5f884dd5027 |
481553962324007 has 2 divisors, whose sum is σ = 481553962324008. Its totient is φ = 481553962324006.
The previous prime is 481553962323979. The next prime is 481553962324037. The reversal of 481553962324007 is 700423269355184.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 481553962324007 - 214 = 481553962307623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (481553962324037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240776981162003 + 240776981162004.
It is an arithmetic number, because the mean of its divisors is an integer number (240776981162004).
It is a 1-persistent number, because it is pandigital, but 2⋅481553962324007 = 963107924648014 is not.
Almost surely, 2481553962324007 is an apocalyptic number.
481553962324007 is a deficient number, since it is larger than the sum of its proper divisors (1).
481553962324007 is an equidigital number, since it uses as much as digits as its factorization.
481553962324007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43545600, while the sum is 59.
The spelling of 481553962324007 in words is "four hundred eighty-one trillion, five hundred fifty-three billion, nine hundred sixty-two million, three hundred twenty-four thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •