Base | Representation |
---|---|
bin | 10101111010101000011001… |
… | …01111010111001100101001 |
3 | 20022122022020122010200202101 |
4 | 22331110030233113030221 |
5 | 22304102344143131133 |
6 | 250300012004533401 |
7 | 13102622165643322 |
oct | 1275241457271451 |
9 | 208568218120671 |
10 | 48194041770793 |
11 | 143a0a84188736 |
12 | 54a43b30b1261 |
13 | 20b78a8c78879 |
14 | bc88657c1449 |
15 | 588986ec037d |
hex | 2bd50cbd7329 |
48194041770793 has 2 divisors, whose sum is σ = 48194041770794. Its totient is φ = 48194041770792.
The previous prime is 48194041770761. The next prime is 48194041770803. The reversal of 48194041770793 is 39707714049184.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38534893691904 + 9659148078889 = 6207648^2 + 3107917^2 .
It is a cyclic number.
It is not a de Polignac number, because 48194041770793 - 25 = 48194041770761 is a prime.
It is not a weakly prime, because it can be changed into another prime (48194041770713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24097020885396 + 24097020885397.
It is an arithmetic number, because the mean of its divisors is an integer number (24097020885397).
Almost surely, 248194041770793 is an apocalyptic number.
It is an amenable number.
48194041770793 is a deficient number, since it is larger than the sum of its proper divisors (1).
48194041770793 is an equidigital number, since it uses as much as digits as its factorization.
48194041770793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42674688, while the sum is 64.
The spelling of 48194041770793 in words is "forty-eight trillion, one hundred ninety-four billion, forty-one million, seven hundred seventy thousand, seven hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •