Base | Representation |
---|---|
bin | 101100111111100111… |
… | …010101111000010011 |
3 | 11121200221101201120222 |
4 | 230333213111320103 |
5 | 1242420322334344 |
6 | 34105540023255 |
7 | 3330133346114 |
oct | 547747257023 |
9 | 147627351528 |
10 | 48311918099 |
11 | 19541900145 |
12 | 9443691b2b |
13 | 472c1070b3 |
14 | 24a446c20b |
15 | 13cb5975ee |
hex | b3f9d5e13 |
48311918099 has 2 divisors, whose sum is σ = 48311918100. Its totient is φ = 48311918098.
The previous prime is 48311918047. The next prime is 48311918113. The reversal of 48311918099 is 99081911384.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-48311918099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 48311918099.
It is not a weakly prime, because it can be changed into another prime (48311968099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24155959049 + 24155959050.
It is an arithmetic number, because the mean of its divisors is an integer number (24155959050).
Almost surely, 248311918099 is an apocalyptic number.
48311918099 is a deficient number, since it is larger than the sum of its proper divisors (1).
48311918099 is an equidigital number, since it uses as much as digits as its factorization.
48311918099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 53.
The spelling of 48311918099 in words is "forty-eight billion, three hundred eleven million, nine hundred eighteen thousand, ninety-nine".
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