Base | Representation |
---|---|
bin | 100011001001110000011… |
… | …0000000000011101010001 |
3 | 122002212110120111111020222 |
4 | 1012103200300000131101 |
5 | 1113124012330444443 |
6 | 14135250332242425 |
7 | 1006023314520035 |
oct | 106234060003521 |
9 | 18085416444228 |
10 | 4831313921873 |
11 | 15a2a4883633a |
12 | 660411310415 |
13 | 29078b40ab5a |
14 | 129ba04161c5 |
15 | 85a18416468 |
hex | 464e0c00751 |
4831313921873 has 2 divisors, whose sum is σ = 4831313921874. Its totient is φ = 4831313921872.
The previous prime is 4831313921827. The next prime is 4831313921933. The reversal of 4831313921873 is 3781293131384.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3299828470849 + 1531485451024 = 1816543^2 + 1237532^2 .
It is a cyclic number.
It is not a de Polignac number, because 4831313921873 - 236 = 4762594445137 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (4831313923873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2415656960936 + 2415656960937.
It is an arithmetic number, because the mean of its divisors is an integer number (2415656960937).
Almost surely, 24831313921873 is an apocalyptic number.
It is an amenable number.
4831313921873 is a deficient number, since it is larger than the sum of its proper divisors (1).
4831313921873 is an equidigital number, since it uses as much as digits as its factorization.
4831313921873 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2612736, while the sum is 53.
The spelling of 4831313921873 in words is "four trillion, eight hundred thirty-one billion, three hundred thirteen million, nine hundred twenty-one thousand, eight hundred seventy-three".
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