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48313313039 = 312472910631
BaseRepresentation
bin101100111111101100…
…101010011100001111
311121201001000121002102
4230333230222130033
51242421202004124
634110025545315
73330151246025
oct547754523417
9147631017072
1048313313039
1119542673192
12944404523b
13472c4a4cc4
1424a4712715
1513cb770aae
hexb3fb2a70f

48313313039 has 12 divisors (see below), whose sum is σ = 49937334480. Its totient is φ = 46740535200.

The previous prime is 48313313033. The next prime is 48313313063. The reversal of 48313313039 is 93031331384.

It is a happy number.

It is not a de Polignac number, because 48313313039 - 24 = 48313313023 is a prime.

It is a super-4 number, since 4×483133130394 (a number of 44 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 48313312993 and 48313313011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48313313033) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4539254 + ... + 4549884.

It is an arithmetic number, because the mean of its divisors is an integer number (4161444540).

Almost surely, 248313313039 is an apocalyptic number.

48313313039 is a deficient number, since it is larger than the sum of its proper divisors (1624021441).

48313313039 is a wasteful number, since it uses less digits than its factorization.

48313313039 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15422 (or 15391 counting only the distinct ones).

The product of its (nonzero) digits is 69984, while the sum is 38.

The spelling of 48313313039 in words is "forty-eight billion, three hundred thirteen million, three hundred thirteen thousand, thirty-nine".

Divisors: 1 31 961 4729 10631 146599 329561 4544569 10216391 50273999 1558493969 48313313039