Base | Representation |
---|---|
bin | 1110000011111010001… |
… | …10110001110100100111 |
3 | 1201012001112020110111222 |
4 | 13001331012301310213 |
5 | 30403430112003322 |
6 | 1005541013250555 |
7 | 46622354001035 |
oct | 7017506616447 |
9 | 1635045213458 |
10 | 483135266087 |
11 | 176995298281 |
12 | 79775033a5b |
13 | 36737198096 |
14 | 195534b5555 |
15 | c87a279e42 |
hex | 707d1b1d27 |
483135266087 has 4 divisors (see below), whose sum is σ = 483807221280. Its totient is φ = 482463310896.
The previous prime is 483135266077. The next prime is 483135266137. The reversal of 483135266087 is 780662531384.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 483135266087 - 24 = 483135266071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (483135266017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335976518 + ... + 335977955.
It is an arithmetic number, because the mean of its divisors is an integer number (120951805320).
Almost surely, 2483135266087 is an apocalyptic number.
483135266087 is a deficient number, since it is larger than the sum of its proper divisors (671955193).
483135266087 is an equidigital number, since it uses as much as digits as its factorization.
483135266087 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 671955192.
The product of its (nonzero) digits is 5806080, while the sum is 53.
The spelling of 483135266087 in words is "four hundred eighty-three billion, one hundred thirty-five million, two hundred sixty-six thousand, eighty-seven".
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