Base | Representation |
---|---|
bin | 1110000100001010100… |
… | …10010100010111000111 |
3 | 1201012102002111010020001 |
4 | 13002011102110113013 |
5 | 30404220230240441 |
6 | 1010002355022131 |
7 | 46625641355545 |
oct | 7020522242707 |
9 | 1635362433201 |
10 | 483272508871 |
11 | 176a55806869 |
12 | 797b2b9a947 |
13 | 3675974b429 |
14 | 195677dcd95 |
15 | c887339731 |
hex | 70854945c7 |
483272508871 has 2 divisors, whose sum is σ = 483272508872. Its totient is φ = 483272508870.
The previous prime is 483272508833. The next prime is 483272508877. The reversal of 483272508871 is 178805272384.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-483272508871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (483272508877) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241636254435 + 241636254436.
It is an arithmetic number, because the mean of its divisors is an integer number (241636254436).
Almost surely, 2483272508871 is an apocalyptic number.
483272508871 is a deficient number, since it is larger than the sum of its proper divisors (1).
483272508871 is an equidigital number, since it uses as much as digits as its factorization.
483272508871 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6021120, while the sum is 55.
The spelling of 483272508871 in words is "four hundred eighty-three billion, two hundred seventy-two million, five hundred eight thousand, eight hundred seventy-one".
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