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4834628769809 is a prime number
BaseRepresentation
bin100011001011010011001…
…0101001001100000010001
3122010012000120222012202202
41012112212111021200101
51113202304431113214
614140555305052545
71006201415332526
oct106264625114021
918105016865682
104834628769809
1115a43999a1693
12660b97487155
13290b990bb537
14129dd677914d
1585b5e44d6de
hex465a6549811

4834628769809 has 2 divisors, whose sum is σ = 4834628769810. Its totient is φ = 4834628769808.

The previous prime is 4834628769797. The next prime is 4834628769811. The reversal of 4834628769809 is 9089678264384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4813320069184 + 21308700625 = 2193928^2 + 145975^2 .

It is a cyclic number.

It is not a de Polignac number, because 4834628769809 - 232 = 4830333802513 is a prime.

Together with 4834628769811, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4834628769109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2417314384904 + 2417314384905.

It is an arithmetic number, because the mean of its divisors is an integer number (2417314384905).

Almost surely, 24834628769809 is an apocalyptic number.

It is an amenable number.

4834628769809 is a deficient number, since it is larger than the sum of its proper divisors (1).

4834628769809 is an equidigital number, since it uses as much as digits as its factorization.

4834628769809 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1003290624, while the sum is 74.

The spelling of 4834628769809 in words is "four trillion, eight hundred thirty-four billion, six hundred twenty-eight million, seven hundred sixty-nine thousand, eight hundred nine".