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48363912481 is a prime number
BaseRepresentation
bin101101000010101101…
…101011110100100001
311121211120020022110211
4231002231223310201
51243022130144411
634115034254121
73331334321203
oct550255536441
9147746208424
1048363912481
1119569193305
129458b87341
134739b101c1
1424ab324773
1513d0e18221
hexb42b6bd21

48363912481 has 2 divisors, whose sum is σ = 48363912482. Its totient is φ = 48363912480.

The previous prime is 48363912439. The next prime is 48363912511. The reversal of 48363912481 is 18421936384.

It is a happy number.

48363912481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35409830625 + 12954081856 = 188175^2 + 113816^2 .

It is a cyclic number.

It is not a de Polignac number, because 48363912481 - 27 = 48363912353 is a prime.

It is a super-2 number, since 2×483639124812 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (48363912431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24181956240 + 24181956241.

It is an arithmetic number, because the mean of its divisors is an integer number (24181956241).

Almost surely, 248363912481 is an apocalyptic number.

It is an amenable number.

48363912481 is a deficient number, since it is larger than the sum of its proper divisors (1).

48363912481 is an equidigital number, since it uses as much as digits as its factorization.

48363912481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 995328, while the sum is 49.

The spelling of 48363912481 in words is "forty-eight billion, three hundred sixty-three million, nine hundred twelve thousand, four hundred eighty-one".