Base | Representation |
---|---|
bin | 10101111111100101110010… |
… | …00100100101001011110011 |
3 | 20100020121001202022221010111 |
4 | 22333302321010211023303 |
5 | 22314400331301120203 |
6 | 250510152052242151 |
7 | 13121133554164603 |
oct | 1277627104451363 |
9 | 210217052287114 |
10 | 48364436738803 |
11 | 14457273754149 |
12 | 5511428010357 |
13 | 20ca9929a1a23 |
14 | bd2bcbaacc03 |
15 | 58d10b33826d |
hex | 2bfcb91252f3 |
48364436738803 has 2 divisors, whose sum is σ = 48364436738804. Its totient is φ = 48364436738802.
The previous prime is 48364436738669. The next prime is 48364436738831. The reversal of 48364436738803 is 30883763446384.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-48364436738803 is a prime.
It is not a weakly prime, because it can be changed into another prime (48364436738833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24182218369401 + 24182218369402.
It is an arithmetic number, because the mean of its divisors is an integer number (24182218369402).
Almost surely, 248364436738803 is an apocalyptic number.
48364436738803 is a deficient number, since it is larger than the sum of its proper divisors (1).
48364436738803 is an equidigital number, since it uses as much as digits as its factorization.
48364436738803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 668860416, while the sum is 67.
The spelling of 48364436738803 in words is "forty-eight trillion, three hundred sixty-four billion, four hundred thirty-six million, seven hundred thirty-eight thousand, eight hundred three".
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