Base | Representation |
---|---|
bin | 10101111111100101110010… |
… | …00100100101101000101011 |
3 | 20100020121001202100000122221 |
4 | 22333302321010211220223 |
5 | 22314400331301200101 |
6 | 250510152052254511 |
7 | 13121133554203153 |
oct | 1277627104455053 |
9 | 210217052300587 |
10 | 48364436740651 |
11 | 14457273755579 |
12 | 5511428011437 |
13 | 20ca9929a2815 |
14 | bd2bcbaad763 |
15 | 58d10b338aa1 |
hex | 2bfcb9125a2b |
48364436740651 has 2 divisors, whose sum is σ = 48364436740652. Its totient is φ = 48364436740650.
The previous prime is 48364436740643. The next prime is 48364436740679. The reversal of 48364436740651 is 15604763446384.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48364436740651 - 23 = 48364436740643 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 48364436740651.
It is not a weakly prime, because it can be changed into another prime (48364436740351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24182218370325 + 24182218370326.
It is an arithmetic number, because the mean of its divisors is an integer number (24182218370326).
Almost surely, 248364436740651 is an apocalyptic number.
48364436740651 is a deficient number, since it is larger than the sum of its proper divisors (1).
48364436740651 is an equidigital number, since it uses as much as digits as its factorization.
48364436740651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139345920, while the sum is 61.
The spelling of 48364436740651 in words is "forty-eight trillion, three hundred sixty-four billion, four hundred thirty-six million, seven hundred forty thousand, six hundred fifty-one".
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