Base | Representation |
---|---|
bin | 10101111111100101110010… |
… | …00100100101101001101101 |
3 | 20100020121001202100000202101 |
4 | 22333302321010211221231 |
5 | 22314400331301200332 |
6 | 250510152052255101 |
7 | 13121133554203306 |
oct | 1277627104455155 |
9 | 210217052300671 |
10 | 48364436740717 |
11 | 14457273755629 |
12 | 5511428011491 |
13 | 20ca9929a2866 |
14 | bd2bcbaad7ad |
15 | 58d10b338ae7 |
hex | 2bfcb9125a6d |
48364436740717 has 32 divisors (see below), whose sum is σ = 51644541634560. Its totient is φ = 45134430432000.
The previous prime is 48364436740693. The next prime is 48364436740727. The reversal of 48364436740717 is 71704763446384.
It is not a de Polignac number, because 48364436740717 - 211 = 48364436738669 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48364436740727) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4881839878 + ... + 4881849784.
It is an arithmetic number, because the mean of its divisors is an integer number (1613891926080).
Almost surely, 248364436740717 is an apocalyptic number.
It is an amenable number.
48364436740717 is a deficient number, since it is larger than the sum of its proper divisors (3280104893843).
48364436740717 is a wasteful number, since it uses less digits than its factorization.
48364436740717 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15201.
The product of its (nonzero) digits is 227598336, while the sum is 64.
The spelling of 48364436740717 in words is "forty-eight trillion, three hundred sixty-four billion, four hundred thirty-six million, seven hundred forty thousand, seven hundred seventeen".
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