Base | Representation |
---|---|
bin | 100011001100001001100… |
… | …0011010101000101101100 |
3 | 122010100201201020022122220 |
4 | 1012120103003111011230 |
5 | 1113220023410041322 |
6 | 14141500304435340 |
7 | 1006264544425254 |
oct | 106302303250554 |
9 | 18110651208586 |
10 | 4836452815212 |
11 | 15a5145589a27 |
12 | 661406318b50 |
13 | 2910c9c7a145 |
14 | 12a12ab10964 |
15 | 85c1965655c |
hex | 466130d516c |
4836452815212 has 12 divisors (see below), whose sum is σ = 11285056568856. Its totient is φ = 1612150938400.
The previous prime is 4836452815127. The next prime is 4836452815213. The reversal of 4836452815212 is 2125182546384.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-3 number, since 3×48364528152123 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (4836452815213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201518867289 + ... + 201518867312.
It is an arithmetic number, because the mean of its divisors is an integer number (940421380738).
Almost surely, 24836452815212 is an apocalyptic number.
It is an amenable number.
4836452815212 is an abundant number, since it is smaller than the sum of its proper divisors (6448603753644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4836452815212 is a wasteful number, since it uses less digits than its factorization.
4836452815212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 403037734608 (or 403037734606 counting only the distinct ones).
The product of its digits is 3686400, while the sum is 51.
The spelling of 4836452815212 in words is "four trillion, eight hundred thirty-six billion, four hundred fifty-two million, eight hundred fifteen thousand, two hundred twelve".
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