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4836452815213 is a prime number
BaseRepresentation
bin100011001100001001100…
…0011010101000101101101
3122010100201201020022122221
41012120103003111011231
51113220023410041323
614141500304435341
71006264544425255
oct106302303250555
918110651208587
104836452815213
1115a5145589a28
12661406318b51
132910c9c7a146
1412a12ab10965
1585c1965655d
hex466130d516d

4836452815213 has 2 divisors, whose sum is σ = 4836452815214. Its totient is φ = 4836452815212.

The previous prime is 4836452815127. The next prime is 4836452815277. The reversal of 4836452815213 is 3125182546384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3750934713289 + 1085518101924 = 1936733^2 + 1041882^2 .

It is a cyclic number.

It is not a de Polignac number, because 4836452815213 - 221 = 4836450718061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4836452815013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2418226407606 + 2418226407607.

It is an arithmetic number, because the mean of its divisors is an integer number (2418226407607).

Almost surely, 24836452815213 is an apocalyptic number.

It is an amenable number.

4836452815213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4836452815213 is an equidigital number, since it uses as much as digits as its factorization.

4836452815213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5529600, while the sum is 52.

The spelling of 4836452815213 in words is "four trillion, eight hundred thirty-six billion, four hundred fifty-two million, eight hundred fifteen thousand, two hundred thirteen".