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483836141413 is a prime number
BaseRepresentation
bin1110000101001101110…
…00011001111101100101
31201020212101001121201101
413002212320121331211
530411344023011123
61010134331400101
746645624226242
oct7024670317545
91636771047641
10483836141413
11177214985289
127992b8b3031
1336819452a01
14195bc5da5c9
15c8bba71aad
hex70a6e19f65

483836141413 has 2 divisors, whose sum is σ = 483836141414. Its totient is φ = 483836141412.

The previous prime is 483836141363. The next prime is 483836141423. The reversal of 483836141413 is 314141638384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 351480608164 + 132355533249 = 592858^2 + 363807^2 .

It is a cyclic number.

It is not a de Polignac number, because 483836141413 - 29 = 483836140901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (483836141423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241918070706 + 241918070707.

It is an arithmetic number, because the mean of its divisors is an integer number (241918070707).

Almost surely, 2483836141413 is an apocalyptic number.

It is an amenable number.

483836141413 is a deficient number, since it is larger than the sum of its proper divisors (1).

483836141413 is an equidigital number, since it uses as much as digits as its factorization.

483836141413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 663552, while the sum is 46.

Adding to 483836141413 its reverse (314141638384), we get a palindrome (797977779797).

The spelling of 483836141413 in words is "four hundred eighty-three billion, eight hundred thirty-six million, one hundred forty-one thousand, four hundred thirteen".