Base | Representation |
---|---|
bin | 1110000101010011000… |
… | …01001000001111001111 |
3 | 1201020222110021201111211 |
4 | 13002221201020033033 |
5 | 30411441333334101 |
6 | 1010142551355251 |
7 | 46650002202022 |
oct | 7025141101717 |
9 | 1636873251454 |
10 | 483880371151 |
11 | 177237944791 |
12 | 79942682b27 |
13 | 3682566a858 |
14 | 195c44311b9 |
15 | c8c08abc51 |
hex | 70a98483cf |
483880371151 has 2 divisors, whose sum is σ = 483880371152. Its totient is φ = 483880371150.
The previous prime is 483880371127. The next prime is 483880371179. The reversal of 483880371151 is 151173088384.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 483880371151 - 211 = 483880369103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 483880371095 and 483880371104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (483880375151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241940185575 + 241940185576.
It is an arithmetic number, because the mean of its divisors is an integer number (241940185576).
Almost surely, 2483880371151 is an apocalyptic number.
483880371151 is a deficient number, since it is larger than the sum of its proper divisors (1).
483880371151 is an equidigital number, since it uses as much as digits as its factorization.
483880371151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 49.
The spelling of 483880371151 in words is "four hundred eighty-three billion, eight hundred eighty million, three hundred seventy-one thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •