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48403630813 is a prime number
BaseRepresentation
bin101101000101000101…
…001100101011011101
311121221022222012210011
4231011011030223131
51243112312141223
634123013443221
73332326034116
oct550505145335
9147838865704
1048403630813
111958965127a
12946a340511
134745108785
1424b270320d
1513d466180d
hexb4514cadd

48403630813 has 2 divisors, whose sum is σ = 48403630814. Its totient is φ = 48403630812.

The previous prime is 48403630799. The next prime is 48403630829. The reversal of 48403630813 is 31803630484.

48403630813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48383721369 + 19909444 = 219963^2 + 4462^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48403630813 is a prime.

It is a super-3 number, since 3×484036308133 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48403600813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24201815406 + 24201815407.

It is an arithmetic number, because the mean of its divisors is an integer number (24201815407).

Almost surely, 248403630813 is an apocalyptic number.

It is an amenable number.

48403630813 is a deficient number, since it is larger than the sum of its proper divisors (1).

48403630813 is an equidigital number, since it uses as much as digits as its factorization.

48403630813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 40.

The spelling of 48403630813 in words is "forty-eight billion, four hundred three million, six hundred thirty thousand, eight hundred thirteen".