Base | Representation |
---|---|
bin | 1110000101101110100… |
… | …10011110011110100111 |
3 | 1201021120120000202202101 |
4 | 13002313102132132213 |
5 | 30412430010123421 |
6 | 1010221523352531 |
7 | 46655506045636 |
oct | 7026722363647 |
9 | 1637516022671 |
10 | 484111411111 |
11 | 1773462a84a9 |
12 | 799a7b22747 |
13 | 368614a22a3 |
14 | 19606db351d |
15 | c8d5ce8191 |
hex | 70b749e7a7 |
484111411111 has 2 divisors, whose sum is σ = 484111411112. Its totient is φ = 484111411110.
The previous prime is 484111411103. The next prime is 484111411151. The reversal of 484111411111 is 111114111484.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 484111411111 - 23 = 484111411103 is a prime.
It is a super-3 number, since 3×4841114111113 (a number of 36 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 484111411111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (484111411151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242055705555 + 242055705556.
It is an arithmetic number, because the mean of its divisors is an integer number (242055705556).
Almost surely, 2484111411111 is an apocalyptic number.
484111411111 is a deficient number, since it is larger than the sum of its proper divisors (1).
484111411111 is an equidigital number, since it uses as much as digits as its factorization.
484111411111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 512, while the sum is 28.
Adding to 484111411111 its reverse (111114111484), we get a palindrome (595225522595).
The spelling of 484111411111 in words is "four hundred eighty-four billion, one hundred eleven million, four hundred eleven thousand, one hundred eleven".
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