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484787305313677 is a prime number
BaseRepresentation
bin110111000111010010101011…
…1000111111111010110001101
32100120111012202211122200212001
41232032211113013333112031
51002020223400130014202
64435020114042512301
7204053504232603622
oct15616452707772615
92316435684580761
10484787305313677
1113051716151a3a3
124645703b805691
1317a673290c1942
14879db8b8d2349
153b0a66c5c0d87
hex1b8e9571ff58d

484787305313677 has 2 divisors, whose sum is σ = 484787305313678. Its totient is φ = 484787305313676.

The previous prime is 484787305313659. The next prime is 484787305313683. The reversal of 484787305313677 is 776313503787484.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 481714089456196 + 3073215857481 = 21947986^2 + 1753059^2 .

It is a cyclic number.

It is not a de Polignac number, because 484787305313677 - 215 = 484787305280909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (484787305313177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242393652656838 + 242393652656839.

It is an arithmetic number, because the mean of its divisors is an integer number (242393652656839).

Almost surely, 2484787305313677 is an apocalyptic number.

It is an amenable number.

484787305313677 is a deficient number, since it is larger than the sum of its proper divisors (1).

484787305313677 is an equidigital number, since it uses as much as digits as its factorization.

484787305313677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1991485440, while the sum is 73.

The spelling of 484787305313677 in words is "four hundred eighty-four trillion, seven hundred eighty-seven billion, three hundred five million, three hundred thirteen thousand, six hundred seventy-seven".