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48510041 is a prime number
BaseRepresentation
bin1011100100001…
…1010001011001
310101021120021012
42321003101121
544404310131
64451423305
71126220456
oct271032131
9111246235
1048510041
1125423348
12142b4b35
13a086188
14662a82d
1543d352b
hex2e43459

48510041 has 2 divisors, whose sum is σ = 48510042. Its totient is φ = 48510040.

The previous prime is 48510037. The next prime is 48510043. The reversal of 48510041 is 14001584.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38875225 + 9634816 = 6235^2 + 3104^2 .

It is a cyclic number.

It is not a de Polignac number, because 48510041 - 22 = 48510037 is a prime.

Together with 48510043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 48509989 and 48510016.

It is not a weakly prime, because it can be changed into another prime (48510043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24255020 + 24255021.

It is an arithmetic number, because the mean of its divisors is an integer number (24255021).

Almost surely, 248510041 is an apocalyptic number.

It is an amenable number.

48510041 is a deficient number, since it is larger than the sum of its proper divisors (1).

48510041 is an equidigital number, since it uses as much as digits as its factorization.

48510041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 640, while the sum is 23.

The square root of 48510041 is about 6964.9150030707. The cubic root of 48510041 is about 364.7068165454.

The spelling of 48510041 in words is "forty-eight million, five hundred ten thousand, forty-one".