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48513027419 is a prime number
BaseRepresentation
bin101101001011100110…
…100000110101011011
311122012221211010201022
4231023212200311123
51243323313334134
634141522313055
73335124633503
oct551346406533
9148187733638
1048513027419
111963538059a
12949aab878b
13476198c2ac
1424c305ca03
1513de07052e
hexb4b9a0d5b

48513027419 has 2 divisors, whose sum is σ = 48513027420. Its totient is φ = 48513027418.

The previous prime is 48513027413. The next prime is 48513027421. The reversal of 48513027419 is 91472031584.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 48513027419 - 216 = 48512961883 is a prime.

It is a super-2 number, since 2×485130274192 (a number of 22 digits) contains 22 as substring.

Together with 48513027421, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 48513027419.

It is not a weakly prime, because it can be changed into another prime (48513027413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24256513709 + 24256513710.

It is an arithmetic number, because the mean of its divisors is an integer number (24256513710).

Almost surely, 248513027419 is an apocalyptic number.

48513027419 is a deficient number, since it is larger than the sum of its proper divisors (1).

48513027419 is an equidigital number, since it uses as much as digits as its factorization.

48513027419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 44.

The spelling of 48513027419 in words is "forty-eight billion, five hundred thirteen million, twenty-seven thousand, four hundred nineteen".