Base | Representation |
---|---|
bin | 1110001000000000111… |
… | …11011100010111011111 |
3 | 1201101202010222112121121 |
4 | 13010000133130113133 |
5 | 30422433411001403 |
6 | 1010543434511411 |
7 | 50031111040225 |
oct | 7040037342737 |
9 | 1641663875547 |
10 | 485339547103 |
11 | 177916581224 |
12 | 7a08b295567 |
13 | 369c8a68188 |
14 | 196c2148b15 |
15 | c958a403bd |
hex | 71007dc5df |
485339547103 has 2 divisors, whose sum is σ = 485339547104. Its totient is φ = 485339547102.
The previous prime is 485339547013. The next prime is 485339547221. The reversal of 485339547103 is 301745933584.
Together with previous prime (485339547013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 485339547103 - 225 = 485305992671 is a prime.
It is a super-3 number, since 3×4853395471033 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (485339647103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242669773551 + 242669773552.
It is an arithmetic number, because the mean of its divisors is an integer number (242669773552).
Almost surely, 2485339547103 is an apocalyptic number.
485339547103 is a deficient number, since it is larger than the sum of its proper divisors (1).
485339547103 is an equidigital number, since it uses as much as digits as its factorization.
485339547103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5443200, while the sum is 52.
The spelling of 485339547103 in words is "four hundred eighty-five billion, three hundred thirty-nine million, five hundred forty-seven thousand, one hundred three".
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