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4856790564881 is a prime number
BaseRepresentation
bin100011010101100111101…
…0001101100000000010001
3122012022020002022001100122
41012223033101230000101
51114033201341034011
614155102341200025
71010614540435133
oct106531721540021
918168202261318
104856790564881
111602831726302
12665341400015
13292cbb60c048
1412b0d9bd5053
1586509d8b3db
hex46acf46c011

4856790564881 has 2 divisors, whose sum is σ = 4856790564882. Its totient is φ = 4856790564880.

The previous prime is 4856790564839. The next prime is 4856790564883. The reversal of 4856790564881 is 1884650976584.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4400198452225 + 456592112656 = 2097665^2 + 675716^2 .

It is a cyclic number.

It is not a de Polignac number, because 4856790564881 - 234 = 4839610695697 is a prime.

It is a super-2 number, since 2×48567905648812 (a number of 26 digits) contains 22 as substring.

Together with 4856790564883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4856790564883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2428395282440 + 2428395282441.

It is an arithmetic number, because the mean of its divisors is an integer number (2428395282441).

Almost surely, 24856790564881 is an apocalyptic number.

It is an amenable number.

4856790564881 is a deficient number, since it is larger than the sum of its proper divisors (1).

4856790564881 is an equidigital number, since it uses as much as digits as its factorization.

4856790564881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 464486400, while the sum is 71.

The spelling of 4856790564881 in words is "four trillion, eight hundred fifty-six billion, seven hundred ninety million, five hundred sixty-four thousand, eight hundred eighty-one".