Base | Representation |
---|---|
bin | 10110000101100001000000… |
… | …10100010111100101111111 |
3 | 20100222001120200110210201202 |
4 | 23002300200110113211333 |
5 | 22331214312243043344 |
6 | 251143502425530115 |
7 | 13141632055535315 |
oct | 1302604024274577 |
9 | 210861520423652 |
10 | 48568032393599 |
11 | 14525650135a84 |
12 | 554498794393b |
13 | 2113c3ac0c294 |
14 | bdc9c352c0b5 |
15 | 5935752b194e |
hex | 2c2c2051797f |
48568032393599 has 2 divisors, whose sum is σ = 48568032393600. Its totient is φ = 48568032393598.
The previous prime is 48568032393571. The next prime is 48568032393631. The reversal of 48568032393599 is 99539323086584.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48568032393599 - 220 = 48568031345023 is a prime.
It is a super-4 number, since 4×485680323935994 (a number of 56 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48568032392599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24284016196799 + 24284016196800.
It is an arithmetic number, because the mean of its divisors is an integer number (24284016196800).
Almost surely, 248568032393599 is an apocalyptic number.
48568032393599 is a deficient number, since it is larger than the sum of its proper divisors (1).
48568032393599 is an equidigital number, since it uses as much as digits as its factorization.
48568032393599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1511654400, while the sum is 74.
The spelling of 48568032393599 in words is "forty-eight trillion, five hundred sixty-eight billion, thirty-two million, three hundred ninety-three thousand, five hundred ninety-nine".
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