Base | Representation |
---|---|
bin | 100011010110000000101… |
… | …0011100011101101110111 |
3 | 122012101101120200111122222 |
4 | 1012230001103203231313 |
5 | 1114041411224303043 |
6 | 14155321523312555 |
7 | 1010644412005043 |
oct | 106540123435567 |
9 | 18171346614588 |
10 | 4857629916023 |
11 | 16031224a4235 |
12 | 66553651b75b |
13 | 2930c348c321 |
14 | 12b179485023 |
15 | 865588d7d68 |
hex | 46b014e3b77 |
4857629916023 has 2 divisors, whose sum is σ = 4857629916024. Its totient is φ = 4857629916022.
The previous prime is 4857629915981. The next prime is 4857629916091. The reversal of 4857629916023 is 3206199267584.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4857629916023 - 28 = 4857629915767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4857629916523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2428814958011 + 2428814958012.
It is an arithmetic number, because the mean of its divisors is an integer number (2428814958012).
It is a 2-persistent number, because it is pandigital, and so is 2⋅4857629916023 = 9715259832046, but 3⋅4857629916023 = 14572889748069 is not.
Almost surely, 24857629916023 is an apocalyptic number.
4857629916023 is a deficient number, since it is larger than the sum of its proper divisors (1).
4857629916023 is an equidigital number, since it uses as much as digits as its factorization.
4857629916023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39191040, while the sum is 62.
The spelling of 4857629916023 in words is "four trillion, eight hundred fifty-seven billion, six hundred twenty-nine million, nine hundred sixteen thousand, twenty-three".
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