Base | Representation |
---|---|
bin | 101101010000010001… |
… | …100110011100110111 |
3 | 11122102102100110212101 |
4 | 231100101212130313 |
5 | 1244003401301404 |
6 | 34153403002531 |
7 | 3340066231663 |
oct | 552021463467 |
9 | 148372313771 |
10 | 48591431479 |
11 | 19675661738 |
12 | 9501209447 |
13 | 4774cb1126 |
14 | 24cd62b8a3 |
15 | 13e5dab2a4 |
hex | b50466737 |
48591431479 has 2 divisors, whose sum is σ = 48591431480. Its totient is φ = 48591431478.
The previous prime is 48591431467. The next prime is 48591431501. The reversal of 48591431479 is 97413419584.
48591431479 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48591431479 - 27 = 48591431351 is a prime.
It is a super-2 number, since 2×485914314792 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48591431579) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24295715739 + 24295715740.
It is an arithmetic number, because the mean of its divisors is an integer number (24295715740).
Almost surely, 248591431479 is an apocalyptic number.
48591431479 is a deficient number, since it is larger than the sum of its proper divisors (1).
48591431479 is an equidigital number, since it uses as much as digits as its factorization.
48591431479 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4354560, while the sum is 55.
The spelling of 48591431479 in words is "forty-eight billion, five hundred ninety-one million, four hundred thirty-one thousand, four hundred seventy-nine".
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