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489032715013 is a prime number
BaseRepresentation
bin1110001110111001001…
…11110000101100000101
31201202021112022220120021
413013130213300230011
531003014333340023
61012354124135141
750221454330503
oct7073447605405
91652245286507
10489032715013
11179441244a07
127a9400974b1
1337166c3912b
141995282b673
15cac2da735d
hex71dc9f0b05

489032715013 has 2 divisors, whose sum is σ = 489032715014. Its totient is φ = 489032715012.

The previous prime is 489032714999. The next prime is 489032715029. The reversal of 489032715013 is 310517230984.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 481327913284 + 7704801729 = 693778^2 + 87777^2 .

It is a cyclic number.

It is not a de Polignac number, because 489032715013 - 29 = 489032714501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (489032715043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 244516357506 + 244516357507.

It is an arithmetic number, because the mean of its divisors is an integer number (244516357507).

Almost surely, 2489032715013 is an apocalyptic number.

It is an amenable number.

489032715013 is a deficient number, since it is larger than the sum of its proper divisors (1).

489032715013 is an equidigital number, since it uses as much as digits as its factorization.

489032715013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 43.

Adding to 489032715013 its reverse (310517230984), we get a palindrome (799549945997).

The spelling of 489032715013 in words is "four hundred eighty-nine billion, thirty-two million, seven hundred fifteen thousand, thirteen".