Base | Representation |
---|---|
bin | 100011100101101001011… |
… | …1101100000011110011011 |
3 | 122022121001222112022211221 |
4 | 1013023102331200132123 |
5 | 1120114200300401021 |
6 | 14222554122432511 |
7 | 1013243540025115 |
oct | 107132275403633 |
9 | 18277058468757 |
10 | 4891212122011 |
11 | 1616395802686 |
12 | 66bb49062737 |
13 | 296315a44227 |
14 | 12ca4356a3b5 |
15 | 87371c5b241 |
hex | 472d2f6079b |
4891212122011 has 2 divisors, whose sum is σ = 4891212122012. Its totient is φ = 4891212122010.
The previous prime is 4891212121981. The next prime is 4891212122021. The reversal of 4891212122011 is 1102212121984.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4891212122011 - 231 = 4889064638363 is a prime.
It is not a weakly prime, because it can be changed into another prime (4891212122021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2445606061005 + 2445606061006.
It is an arithmetic number, because the mean of its divisors is an integer number (2445606061006).
Almost surely, 24891212122011 is an apocalyptic number.
4891212122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4891212122011 is an equidigital number, since it uses as much as digits as its factorization.
4891212122011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 34.
Adding to 4891212122011 its reverse (1102212121984), we get a palindrome (5993424243995).
The spelling of 4891212122011 in words is "four trillion, eight hundred ninety-one billion, two hundred twelve million, one hundred twenty-two thousand, eleven".
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