Base | Representation |
---|---|
bin | 101101100011011011… |
… | …000000001101001111 |
3 | 11200020210210202012000 |
4 | 231203123000031033 |
5 | 1300133120212000 |
6 | 34245320043343 |
7 | 3351046531062 |
oct | 554333001517 |
9 | 150223722160 |
10 | 48912663375 |
11 | 1981aa17a44 |
12 | 9590903553 |
13 | 47c6703c84 |
14 | 252016a8d9 |
15 | 14141b1000 |
hex | b636c034f |
48912663375 has 64 divisors (see below), whose sum is σ = 92878481280. Its totient is φ = 25381641600.
The previous prime is 48912663367. The next prime is 48912663383. The reversal of 48912663375 is 57336621984.
48912663375 is a `hidden beast` number, since 4 + 8 + 9 + 1 + 266 + 3 + 375 = 666.
48912663375 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (48912663367) and next prime (48912663383).
It is not a de Polignac number, because 48912663375 - 23 = 48912663367 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 70972 + ... + 320721.
It is an arithmetic number, because the mean of its divisors is an integer number (1451226270).
Almost surely, 248912663375 is an apocalyptic number.
48912663375 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
48912663375 is a deficient number, since it is larger than the sum of its proper divisors (43965817905).
48912663375 is a wasteful number, since it uses less digits than its factorization.
48912663375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391754 (or 391738 counting only the distinct ones).
The product of its digits is 6531840, while the sum is 54.
The spelling of 48912663375 in words is "forty-eight billion, nine hundred twelve million, six hundred sixty-three thousand, three hundred seventy-five".
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