Base | Representation |
---|---|
bin | 101101101000111110… |
… | …000010100111000011 |
3 | 11200111021221020112202 |
4 | 231220332002213003 |
5 | 1300330431444324 |
6 | 34302442543415 |
7 | 3353256604022 |
oct | 555076024703 |
9 | 150437836482 |
10 | 49005734339 |
11 | 198685065a1 |
12 | 95b7b07b6b |
13 | 480ca8c953 |
14 | 252c6768b9 |
15 | 141c4478ae |
hex | b68f829c3 |
49005734339 has 2 divisors, whose sum is σ = 49005734340. Its totient is φ = 49005734338.
The previous prime is 49005734321. The next prime is 49005734431. The reversal of 49005734339 is 93343750094.
49005734339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49005734339 - 232 = 44710767043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49005734293 and 49005734302.
It is not a weakly prime, because it can be changed into another prime (49005730339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24502867169 + 24502867170.
It is an arithmetic number, because the mean of its divisors is an integer number (24502867170).
Almost surely, 249005734339 is an apocalyptic number.
49005734339 is a deficient number, since it is larger than the sum of its proper divisors (1).
49005734339 is an equidigital number, since it uses as much as digits as its factorization.
49005734339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 47.
The spelling of 49005734339 in words is "forty-nine billion, five million, seven hundred thirty-four thousand, three hundred thirty-nine".
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