Base | Representation |
---|---|
bin | 101101101010000010… |
… | …101001100111111101 |
3 | 11200112112210000010212 |
4 | 231222002221213331 |
5 | 1300400033014213 |
6 | 34304324242205 |
7 | 3353565513116 |
oct | 555202514775 |
9 | 150475700125 |
10 | 49023719933 |
11 | 19877680421 |
12 | 9601b40365 |
13 | 4813719206 |
14 | 2530bd920d |
15 | 141dceb9a8 |
hex | b6a0a99fd |
49023719933 has 2 divisors, whose sum is σ = 49023719934. Its totient is φ = 49023719932.
The previous prime is 49023719917. The next prime is 49023719939. The reversal of 49023719933 is 33991732094.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49023716569 + 3364 = 221413^2 + 58^2 .
It is a cyclic number.
It is not a de Polignac number, because 49023719933 - 24 = 49023719917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49023719939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24511859966 + 24511859967.
It is an arithmetic number, because the mean of its divisors is an integer number (24511859967).
Almost surely, 249023719933 is an apocalyptic number.
It is an amenable number.
49023719933 is a deficient number, since it is larger than the sum of its proper divisors (1).
49023719933 is an equidigital number, since it uses as much as digits as its factorization.
49023719933 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1102248, while the sum is 50.
The spelling of 49023719933 in words is "forty-nine billion, twenty-three million, seven hundred nineteen thousand, nine hundred thirty-three".
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