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490246588373 is a prime number
BaseRepresentation
bin1110010001001001111…
…10010100011111010101
31201212102010110001202212
413020210332110133111
531013011111311443
61013114405443205
750263524150053
oct7104476243725
91655363401685
10490246588373
11179a04466a33
127b01a710505
13372cb57a1a9
1419a29b2d1d3
15cb44733618
hex7224f947d5

490246588373 has 2 divisors, whose sum is σ = 490246588374. Its totient is φ = 490246588372.

The previous prime is 490246588333. The next prime is 490246588379. The reversal of 490246588373 is 373885642094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 476980847044 + 13265741329 = 690638^2 + 115177^2 .

It is a cyclic number.

It is not a de Polignac number, because 490246588373 - 222 = 490242394069 is a prime.

It is a super-2 number, since 2×4902465883732 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (490246588379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245123294186 + 245123294187.

It is an arithmetic number, because the mean of its divisors is an integer number (245123294187).

Almost surely, 2490246588373 is an apocalyptic number.

It is an amenable number.

490246588373 is a deficient number, since it is larger than the sum of its proper divisors (1).

490246588373 is an equidigital number, since it uses as much as digits as its factorization.

490246588373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34836480, while the sum is 59.

The spelling of 490246588373 in words is "four hundred ninety billion, two hundred forty-six million, five hundred eighty-eight thousand, three hundred seventy-three".