4903198141 has 2 divisors, whose sum is σ = 4903198142. Its totient is φ = 4903198140.

The previous prime is 4903198133. The next prime is 4903198151. The reversal of 4903198141 is 1418913094.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4641696900 + 261501241 = 68130^2 + 16171^2 .

It is a cyclic number.

It is not a de Polignac number, because 4903198141 - 2³ = 4903198133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4903198094 and 4903198103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4903198151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2451599070 + 2451599071.

It is an arithmetic number, because the mean of its divisors is an integer number (2451599071).

Almost surely, 2^4903198141 is an apocalyptic number.

It is an amenable number.

4903198141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4903198141 is an equidigital number, since it uses as much as digits as its factorization.

4903198141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 40.

The square root of 4903198141 is about 70022.8401380578. The cubic root of 4903198141 is about 1698.8686984137.

The spelling of 4903198141 in words is "four billion, nine hundred three million, one hundred ninety-eight thousand, one hundred forty-one".