Base | Representation |
---|---|
bin | 101101101011100100… |
… | …011011001100100111 |
3 | 11200121100000012021211 |
4 | 231223210123030213 |
5 | 1300423113212301 |
6 | 34311041452251 |
7 | 3354326414116 |
oct | 555344331447 |
9 | 150540005254 |
10 | 49049350951 |
11 | 19890097387 |
12 | 960a641087 |
13 | 4818b216b3 |
14 | 253438bc7d |
15 | 14211b1051 |
hex | b6b91b327 |
49049350951 has 2 divisors, whose sum is σ = 49049350952. Its totient is φ = 49049350950.
The previous prime is 49049350939. The next prime is 49049350957. The reversal of 49049350951 is 15905394094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49049350951 - 29 = 49049350439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49049350895 and 49049350904.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49049350957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24524675475 + 24524675476.
It is an arithmetic number, because the mean of its divisors is an integer number (24524675476).
Almost surely, 249049350951 is an apocalyptic number.
49049350951 is a deficient number, since it is larger than the sum of its proper divisors (1).
49049350951 is an equidigital number, since it uses as much as digits as its factorization.
49049350951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 874800, while the sum is 49.
The spelling of 49049350951 in words is "forty-nine billion, forty-nine million, three hundred fifty thousand, nine hundred fifty-one".
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