Base | Representation |
---|---|
bin | 1110010001101001000… |
… | …00100001101001111001 |
3 | 1201220002021212012010212 |
4 | 13020310200201221321 |
5 | 31014024321312213 |
6 | 1013200315520505 |
7 | 50303140343636 |
oct | 7106440415171 |
9 | 1656067765125 |
10 | 490507213433 |
11 | 17a028597446 |
12 | 7b091a59135 |
13 | 3734056cac3 |
14 | 19a525b318d |
15 | cb5c5659a8 |
hex | 7234821a79 |
490507213433 has 2 divisors, whose sum is σ = 490507213434. Its totient is φ = 490507213432.
The previous prime is 490507213393. The next prime is 490507213439. The reversal of 490507213433 is 334312705094.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 393233088889 + 97274124544 = 627083^2 + 311888^2 .
It is a cyclic number.
It is not a de Polignac number, because 490507213433 - 26 = 490507213369 is a prime.
It is not a weakly prime, because it can be changed into another prime (490507213439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245253606716 + 245253606717.
It is an arithmetic number, because the mean of its divisors is an integer number (245253606717).
Almost surely, 2490507213433 is an apocalyptic number.
It is an amenable number.
490507213433 is a deficient number, since it is larger than the sum of its proper divisors (1).
490507213433 is an equidigital number, since it uses as much as digits as its factorization.
490507213433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 272160, while the sum is 41.
The spelling of 490507213433 in words is "four hundred ninety billion, five hundred seven million, two hundred thirteen thousand, four hundred thirty-three".
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