Base | Representation |
---|---|
bin | 10110010011111001001100… |
… | …10011010011100010110011 |
3 | 20102201021201220022112022021 |
4 | 23021330212103103202303 |
5 | 22412313041312022303 |
6 | 252202444011452311 |
7 | 13222421302210123 |
oct | 1311744623234263 |
9 | 212637656275267 |
10 | 49062054017203 |
11 | 146a61114a1837 |
12 | 560467a757097 |
13 | 214b6bb5c2716 |
14 | c1888a770c83 |
15 | 5a133b12debd |
hex | 2c9f264d38b3 |
49062054017203 has 2 divisors, whose sum is σ = 49062054017204. Its totient is φ = 49062054017202.
The previous prime is 49062054017173. The next prime is 49062054017231. The reversal of 49062054017203 is 30271045026094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49062054017203 - 29 = 49062054016691 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49062054017203.
It is not a weakly prime, because it can be changed into another prime (49062054017503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24531027008601 + 24531027008602.
It is an arithmetic number, because the mean of its divisors is an integer number (24531027008602).
Almost surely, 249062054017203 is an apocalyptic number.
49062054017203 is a deficient number, since it is larger than the sum of its proper divisors (1).
49062054017203 is an equidigital number, since it uses as much as digits as its factorization.
49062054017203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 49062054017203 in words is "forty-nine trillion, sixty-two billion, fifty-four million, seventeen thousand, two hundred three".
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