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49062054017173 is a prime number
BaseRepresentation
bin10110010011111001001100…
…10011010011100010010101
320102201021201220022112021011
423021330212103103202111
522412313041312022143
6252202444011452221
713222421302210051
oct1311744623234225
9212637656275234
1049062054017173
11146a61114a180a
12560467a757071
13214b6bb5c26c2
14c1888a770c61
155a133b12de9d
hex2c9f264d3895

49062054017173 has 2 divisors, whose sum is σ = 49062054017174. Its totient is φ = 49062054017172.

The previous prime is 49062054017107. The next prime is 49062054017203. The reversal of 49062054017173 is 37171045026094.

49062054017173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43182680250609 + 5879373766564 = 6571353^2 + 2424742^2 .

It is a cyclic number.

It is not a de Polignac number, because 49062054017173 - 217 = 49062053886101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49062054017773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24531027008586 + 24531027008587.

It is an arithmetic number, because the mean of its divisors is an integer number (24531027008587).

Almost surely, 249062054017173 is an apocalyptic number.

It is an amenable number.

49062054017173 is a deficient number, since it is larger than the sum of its proper divisors (1).

49062054017173 is an equidigital number, since it uses as much as digits as its factorization.

49062054017173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1270080, while the sum is 49.

The spelling of 49062054017173 in words is "forty-nine trillion, sixty-two billion, fifty-four million, seventeen thousand, one hundred seventy-three".