Base | Representation |
---|---|
bin | 11101001111110… |
… | …011110010011111 |
3 | 1021012022022021212 |
4 | 131033303302133 |
5 | 2001103333201 |
6 | 120405015035 |
7 | 15105512201 |
oct | 3517636237 |
9 | 1235268255 |
10 | 490683551 |
11 | 231a838a6 |
12 | 1183b447b |
13 | 7a8726c7 |
14 | 4924c771 |
15 | 2d127abb |
hex | 1d3f3c9f |
490683551 has 2 divisors, whose sum is σ = 490683552. Its totient is φ = 490683550.
The previous prime is 490683547. The next prime is 490683581. The reversal of 490683551 is 155386094.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 490683551 - 22 = 490683547 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 490683499 and 490683508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (490683511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245341775 + 245341776.
It is an arithmetic number, because the mean of its divisors is an integer number (245341776).
Almost surely, 2490683551 is an apocalyptic number.
490683551 is a deficient number, since it is larger than the sum of its proper divisors (1).
490683551 is an equidigital number, since it uses as much as digits as its factorization.
490683551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 41.
The square root of 490683551 is about 22151.3780835414. The cubic root of 490683551 is about 788.7399401973.
The spelling of 490683551 in words is "four hundred ninety million, six hundred eighty-three thousand, five hundred fifty-one".
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