Base | Representation |
---|---|
bin | 1110010010010001100… |
… | …00110111000111111001 |
3 | 1201220221222022011112202 |
4 | 13021020300313013321 |
5 | 31020223320234433 |
6 | 1013254135315545 |
7 | 50314434666632 |
oct | 7111060670771 |
9 | 1656858264482 |
10 | 490847039993 |
11 | 17a1923a3142 |
12 | 7b16781bbb5 |
13 | 37395aa34cb |
14 | 19a85792889 |
15 | cb7c2deee8 |
hex | 7248c371f9 |
490847039993 has 2 divisors, whose sum is σ = 490847039994. Its totient is φ = 490847039992.
The previous prime is 490847039987. The next prime is 490847040023. The reversal of 490847039993 is 399930748094.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 483766154089 + 7080885904 = 695533^2 + 84148^2 .
It is a cyclic number.
It is not a de Polignac number, because 490847039993 - 26 = 490847039929 is a prime.
It is not a weakly prime, because it can be changed into another prime (490847035993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245423519996 + 245423519997.
It is an arithmetic number, because the mean of its divisors is an integer number (245423519997).
Almost surely, 2490847039993 is an apocalyptic number.
It is an amenable number.
490847039993 is a deficient number, since it is larger than the sum of its proper divisors (1).
490847039993 is an equidigital number, since it uses as much as digits as its factorization.
490847039993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52907904, while the sum is 65.
The spelling of 490847039993 in words is "four hundred ninety billion, eight hundred forty-seven million, thirty-nine thousand, nine hundred ninety-three".
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