Base | Representation |
---|---|
bin | 1110010010011001011… |
… | …01001110010100110101 |
3 | 1201221010120210012120221 |
4 | 13021030231032110311 |
5 | 31020342234222232 |
6 | 1013304501254341 |
7 | 50316200211406 |
oct | 7111455162465 |
9 | 1657116705527 |
10 | 490913195317 |
11 | 17a216778666 |
12 | 7b185a043b1 |
13 | 373a66c707c |
14 | 19a904939ad |
15 | cb8300b897 |
hex | 724cb4e535 |
490913195317 has 2 divisors, whose sum is σ = 490913195318. Its totient is φ = 490913195316.
The previous prime is 490913195273. The next prime is 490913195401. The reversal of 490913195317 is 713591319094.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 478323008881 + 12590186436 = 691609^2 + 112206^2 .
It is a cyclic number.
It is not a de Polignac number, because 490913195317 - 235 = 456553456949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (490913195417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245456597658 + 245456597659.
It is an arithmetic number, because the mean of its divisors is an integer number (245456597659).
Almost surely, 2490913195317 is an apocalyptic number.
It is an amenable number.
490913195317 is a deficient number, since it is larger than the sum of its proper divisors (1).
490913195317 is an equidigital number, since it uses as much as digits as its factorization.
490913195317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 918540, while the sum is 52.
The spelling of 490913195317 in words is "four hundred ninety billion, nine hundred thirteen million, one hundred ninety-five thousand, three hundred seventeen".
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