Base | Representation |
---|---|
bin | 1001001001010101… |
… | …00111010011110101 |
3 | 110200012020211211011 |
4 | 10210222213103311 |
5 | 40023442240013 |
6 | 2131120512221 |
7 | 232451213134 |
oct | 44452472365 |
9 | 13605224734 |
10 | 4910118133 |
11 | 209a6a7478 |
12 | b5047b671 |
13 | 60334b65b |
14 | 34818591b |
15 | 1db0eec3d |
hex | 124aa74f5 |
4910118133 has 2 divisors, whose sum is σ = 4910118134. Its totient is φ = 4910118132.
The previous prime is 4910118113. The next prime is 4910118173. The reversal of 4910118133 is 3318110194.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4741975044 + 168143089 = 68862^2 + 12967^2 .
It is a cyclic number.
It is not a de Polignac number, because 4910118133 - 221 = 4908020981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4910118095 and 4910118104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4910118113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2455059066 + 2455059067.
It is an arithmetic number, because the mean of its divisors is an integer number (2455059067).
Almost surely, 24910118133 is an apocalyptic number.
It is an amenable number.
4910118133 is a deficient number, since it is larger than the sum of its proper divisors (1).
4910118133 is an equidigital number, since it uses as much as digits as its factorization.
4910118133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 31.
The square root of 4910118133 is about 70072.2351077800. The cubic root of 4910118133 is about 1699.6675397156.
The spelling of 4910118133 in words is "four billion, nine hundred ten million, one hundred eighteen thousand, one hundred thirty-three".
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