Base | Representation |
---|---|
bin | 110111110101001110110001… |
… | …0101011100001000010001001 |
3 | 2101101211210210010022220012120 |
4 | 1233222131202223201002021 |
5 | 1003332200023340214233 |
6 | 4500252421542401453 |
7 | 205304612046365352 |
oct | 15752354253410211 |
9 | 2341753703286176 |
10 | 491101101101193 |
11 | 132530897657430 |
12 | 470b6825130289 |
13 | 1810483448b6cb |
14 | 893b5c4b3cd29 |
15 | 3bb99eee5d4b3 |
hex | 1bea762ae1089 |
491101101101193 has 32 divisors (see below), whose sum is σ = 752109746895360. Its totient is φ = 281902693069440.
The previous prime is 491101101101189. The next prime is 491101101101201. The reversal of 491101101101193 is 391101101101194.
It is not a de Polignac number, because 491101101101193 - 22 = 491101101101189 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (491101101101693) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 93598371 + ... + 98705912.
It is an arithmetic number, because the mean of its divisors is an integer number (23503429590480).
Almost surely, 2491101101101193 is an apocalyptic number.
It is an amenable number.
491101101101193 is a deficient number, since it is larger than the sum of its proper divisors (261008645794167).
491101101101193 is a wasteful number, since it uses less digits than its factorization.
491101101101193 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192308389.
The product of its (nonzero) digits is 972, while the sum is 33.
Subtracting from 491101101101193 its reverse (391101101101194), we obtain a palindrome (99999999999999).
The spelling of 491101101101193 in words is "four hundred ninety-one trillion, one hundred one billion, one hundred one million, one hundred one thousand, one hundred ninety-three".
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