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491101101101201 is a prime number
BaseRepresentation
bin110111110101001110110001…
…0101011100001000010010001
32101101211210210010022220012212
41233222131202223201002101
51003332200023340214301
64500252421542401505
7205304612046365363
oct15752354253410221
92341753703286185
10491101101101201
11132530897657438
12470b6825130295
131810483448b706
14893b5c4b3cd33
153bb99eee5d4bb
hex1bea762ae1091

491101101101201 has 2 divisors, whose sum is σ = 491101101101202. Its totient is φ = 491101101101200.

The previous prime is 491101101101189. The next prime is 491101101101239. The reversal of 491101101101201 is 102101101101194.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 358881804318976 + 132219296782225 = 18944176^2 + 11498665^2 .

It is a cyclic number.

It is not a de Polignac number, because 491101101101201 - 214 = 491101101084817 is a prime.

It is not a weakly prime, because it can be changed into another prime (491101101101701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245550550550600 + 245550550550601.

It is an arithmetic number, because the mean of its divisors is an integer number (245550550550601).

Almost surely, 2491101101101201 is an apocalyptic number.

It is an amenable number.

491101101101201 is a deficient number, since it is larger than the sum of its proper divisors (1).

491101101101201 is an equidigital number, since it uses as much as digits as its factorization.

491101101101201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 23.

Adding to 491101101101201 its reverse (102101101101194), we get a palindrome (593202202202395).

The spelling of 491101101101201 in words is "four hundred ninety-one trillion, one hundred one billion, one hundred one million, one hundred one thousand, two hundred one".