Base | Representation |
---|---|
bin | 110111110101010011011000… |
… | …0101101001111100001011101 |
3 | 2101101212202100000001201002201 |
4 | 1233222212300231033201131 |
5 | 1003332330312012024242 |
6 | 4500301140120451501 |
7 | 205305412256523004 |
oct | 15752466055174135 |
9 | 2341782300051081 |
10 | 491111000111197 |
11 | 132535007364134 |
12 | 470b8728319b91 |
13 | 1810575127988b |
14 | 893bc836d3c3b |
15 | 3bb9dce01d4b7 |
hex | 1bea9b0b4f85d |
491111000111197 has 2 divisors, whose sum is σ = 491111000111198. Its totient is φ = 491111000111196.
The previous prime is 491111000111131. The next prime is 491111000111261. The reversal of 491111000111197 is 791111000111194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 486544290947001 + 4566709164196 = 22057749^2 + 2136986^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-491111000111197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (491111000111117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245555500055598 + 245555500055599.
It is an arithmetic number, because the mean of its divisors is an integer number (245555500055599).
Almost surely, 2491111000111197 is an apocalyptic number.
It is an amenable number.
491111000111197 is a deficient number, since it is larger than the sum of its proper divisors (1).
491111000111197 is an equidigital number, since it uses as much as digits as its factorization.
491111000111197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 37.
The spelling of 491111000111197 in words is "four hundred ninety-one trillion, one hundred eleven billion, one hundred eleven thousand, one hundred ninety-seven".
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