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491111353 is a prime number
BaseRepresentation
bin11101010001011…
…100001110111001
31021020010001010101
4131101130032321
52001211030403
6120422115401
715112243345
oct3521341671
91236101111
10491111353
11232246257
1211857bb61
137a992345
1449320625
152d1ae71d
hex1d45c3b9

491111353 has 2 divisors, whose sum is σ = 491111354. Its totient is φ = 491111352.

The previous prime is 491111329. The next prime is 491111377. The reversal of 491111353 is 353111194.

It is a balanced prime because it is at equal distance from previous prime (491111329) and next prime (491111377).

It can be written as a sum of positive squares in only one way, i.e., 371602729 + 119508624 = 19277^2 + 10932^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-491111353 is a prime.

It is a super-2 number, since 2×4911113532 = 482380722090981218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (491111053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245555676 + 245555677.

It is an arithmetic number, because the mean of its divisors is an integer number (245555677).

Almost surely, 2491111353 is an apocalyptic number.

It is an amenable number.

491111353 is a deficient number, since it is larger than the sum of its proper divisors (1).

491111353 is an equidigital number, since it uses as much as digits as its factorization.

491111353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1620, while the sum is 28.

The square root of 491111353 is about 22161.0323089878. The cubic root of 491111353 is about 788.9690943434.

The spelling of 491111353 in words is "four hundred ninety-one million, one hundred eleven thousand, three hundred fifty-three".