Base | Representation |
---|---|
bin | 100011101110111110101… |
… | …1111000000000011011101 |
3 | 122101111210122210020020222 |
4 | 1013131331133000003131 |
5 | 1120431221220214023 |
6 | 14240110510051125 |
7 | 1014553265561360 |
oct | 107357537000335 |
9 | 18344718706228 |
10 | 4911252898013 |
11 | 162393a252280 |
12 | 673a007a9aa5 |
13 | 29818a9c7977 |
14 | 12d9c50280d7 |
15 | 87b4637dcc8 |
hex | 4777d7c00dd |
4911252898013 has 32 divisors (see below), whose sum is σ = 6186843666432. Its totient is φ = 3787174728000.
The previous prime is 4911252897977. The next prime is 4911252898043. The reversal of 4911252898013 is 3108982521194.
It is a cyclic number.
It is not a de Polignac number, because 4911252898013 - 230 = 4910179156189 is a prime.
It is a Smith number, since the sum of its digits (53) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4911252898043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11294495 + ... + 11721267.
It is an arithmetic number, because the mean of its divisors is an integer number (193338864576).
Almost surely, 24911252898013 is an apocalyptic number.
It is an amenable number.
4911252898013 is a deficient number, since it is larger than the sum of its proper divisors (1275590768419).
4911252898013 is a wasteful number, since it uses less digits than its factorization.
4911252898013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428345.
The product of its (nonzero) digits is 1244160, while the sum is 53.
The spelling of 4911252898013 in words is "four trillion, nine hundred eleven billion, two hundred fifty-two million, eight hundred ninety-eight thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •