Base | Representation |
---|---|
bin | 101101101111010111… |
… | …111111111001111101 |
3 | 11200202210011011212122 |
4 | 231233113333321331 |
5 | 1301040434433201 |
6 | 34321242212325 |
7 | 3356033221502 |
oct | 555727777175 |
9 | 150683134778 |
10 | 49113202301 |
11 | 19913138899 |
12 | 9627ab40a5 |
13 | 4829119667 |
14 | 253ca4d4a9 |
15 | 1426ac4e1b |
hex | b6f5ffe7d |
49113202301 has 2 divisors, whose sum is σ = 49113202302. Its totient is φ = 49113202300.
The previous prime is 49113202291. The next prime is 49113202309. The reversal of 49113202301 is 10320231194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42065599801 + 7047602500 = 205099^2 + 83950^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49113202301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49113202309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24556601150 + 24556601151.
It is an arithmetic number, because the mean of its divisors is an integer number (24556601151).
Almost surely, 249113202301 is an apocalyptic number.
It is an amenable number.
49113202301 is a deficient number, since it is larger than the sum of its proper divisors (1).
49113202301 is an equidigital number, since it uses as much as digits as its factorization.
49113202301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 49113202301 its reverse (10320231194), we get a palindrome (59433433495).
The spelling of 49113202301 in words is "forty-nine billion, one hundred thirteen million, two hundred two thousand, three hundred one".
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