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49114533749 is a prime number
BaseRepresentation
bin101101101111011101…
…000100111101110101
311200202212122211021112
4231233131010331311
51301041310034444
634321330524405
73356050435331
oct555735047565
9150685584245
1049114533749
1119913968166
129628436705
1348294946b8
14253ccb87c1
151426c8969e
hexb6f744f75

49114533749 has 2 divisors, whose sum is σ = 49114533750. Its totient is φ = 49114533748.

The previous prime is 49114533733. The next prime is 49114533803. The reversal of 49114533749 is 94733541194.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29857420849 + 19257112900 = 172793^2 + 138770^2 .

It is a cyclic number.

It is not a de Polignac number, because 49114533749 - 24 = 49114533733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 49114533697 and 49114533706.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49114533449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24557266874 + 24557266875.

It is an arithmetic number, because the mean of its divisors is an integer number (24557266875).

Almost surely, 249114533749 is an apocalyptic number.

It is an amenable number.

49114533749 is a deficient number, since it is larger than the sum of its proper divisors (1).

49114533749 is an equidigital number, since it uses as much as digits as its factorization.

49114533749 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1632960, while the sum is 50.

The spelling of 49114533749 in words is "forty-nine billion, one hundred fourteen million, five hundred thirty-three thousand, seven hundred forty-nine".